Trigonometric Ratios are 

What are sin cos tan? - Chapter 8 Class 10  - Trignometric Ratios

∠A 30° 45° 60° 90°
Sin A 0 1\2 1\2 3\2 1
Cos A 1 3\2 1\2 1\2 0
tan A 0 1\3 1 3  
cosec A Not defined 2 2 2\3 1
sec A 1 2\3 2 2 Not defined
cot A Not defined 3 1 1/3 0

 

  1. Chapter 8 Class 10 Introduction to Trignometry
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sin πœƒ = (𝑠𝑖𝑑𝑒 π‘œπ‘π‘π‘œπ‘ π‘–π‘‘π‘’ π‘‘π‘œ π‘Žπ‘›π‘”π‘™π‘’ πœƒ)/β„Žπ‘¦π‘π‘œπ‘‘π‘’π‘›π‘’π‘ π‘’=𝐴𝐡/𝐡𝐢 cos πœƒ =(𝑠𝑖𝑑𝑒 π‘œπ‘π‘π‘œπ‘ π‘–π‘‘π‘’ π‘‘π‘œ π‘Žπ‘›π‘”π‘™π‘’ πœƒ)/β„Žπ‘¦π‘π‘œπ‘‘π‘’π‘›π‘’π‘ π‘’=𝐡𝐢/𝐴𝐢 tan πœƒ =(𝑠𝑖𝑑𝑒 π‘œπ‘π‘π‘œπ‘ π‘–π‘‘π‘’ π‘‘π‘œ π‘Žπ‘›π‘”π‘™π‘’ πœƒ)/(𝑠𝑖𝑑𝑒 π‘Žπ‘‘π‘—π‘Žπ‘π‘’π‘›π‘‘ π‘‘π‘œ π‘Žπ‘›π‘”π‘™π‘’ πœƒ)=𝐴𝐡/𝐡𝐢 Also, tan πœƒ = sinβ‘πœƒ/cosβ‘πœƒ =((𝐴𝐡/𝐴𝐢)/𝐡𝐢)/𝐴𝐢=𝐴𝐡/𝐡𝐢 sec πœƒ = 1/cosβ‘πœƒ =𝐴𝐢/𝐡𝐢 cosec πœƒ = 1/sinβ‘πœƒ =𝐴𝐢/𝐴𝐡 cot πœƒ = 1/tanβ‘πœƒ =𝐡𝐢/𝐴𝐡

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Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He provides courses for Mathematics from Class 9 to 12. You can contact him here.
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