 
 
 
 Integration by specific formulaes - Formula 4
Integration by specific formulaes - Formula 4
Last updated at December 16, 2024 by Teachoo
  
 
 
 Transcript
Example 9 Find the following integrals: (iii)  𝑑𝑥 5 𝑥2 − 2𝑥   𝑑𝑥 5 𝑥2 − 2𝑥  =  𝑑𝑥 5 𝑥2 − 25𝑥  =  𝑑𝑥 5 𝑥2 − 2 𝑥 15  =  𝑑𝑥 5 𝑥2 − 2 𝑥 15 + 152− 152  =  𝑑𝑥 5 𝑥 − 152− 152  =  𝑑𝑥 5  𝑥 − 152− 152 =  𝑑𝑥 5  𝑥 − 152− 152 = 1 5 𝑙𝑜𝑔 𝑥− 15+  𝑥− 152− 152+𝐶1 = 1 5𝑙𝑜𝑔 𝑥− 15+  𝑥− 152− 152+ 𝐶1 5 = 1 5𝑙𝑜𝑔 𝑥− 15+  𝑥2+ 152−2 𝑥 15− 152+𝐶 = 1 5𝑙𝑜𝑔 𝑥− 15+  𝑥2− 2𝑥5+𝐶