Arithmetic Progression
Question 2 Deleted for CBSE Board 2024 Exams
Question 3 Important Deleted for CBSE Board 2024 Exams
Question 4 Deleted for CBSE Board 2024 Exams
Question 5 Important Deleted for CBSE Board 2024 Exams
Question 6 Deleted for CBSE Board 2024 Exams
Question 7 Important Deleted for CBSE Board 2024 Exams
Question 8 Deleted for CBSE Board 2024 Exams
Question 9 Important Deleted for CBSE Board 2024 Exams
Question 10 Deleted for CBSE Board 2024 Exams
Question 11 Important Deleted for CBSE Board 2024 Exams
Question 12 Deleted for CBSE Board 2024 Exams
Question 13 Deleted for CBSE Board 2024 Exams
Question 14 Important Deleted for CBSE Board 2024 Exams You are here
Question 15 Important Deleted for CBSE Board 2024 Exams
Question 16 Important Deleted for CBSE Board 2024 Exams
Question 17 Deleted for CBSE Board 2024 Exams
Question 18 Important Deleted for CBSE Board 2024 Exams
Arithmetic Progression
Last updated at April 16, 2024 by Teachoo
Ex9.2,14 Insert five numbers between 8 and 26 such that the resulting sequence is an A.P. We know that to insert n numbers between a & b common difference (d) = ( )/( + 1) Here, We need to insert 5 numbers between 8 and 26 So, b = 26 , a = 8 & number of terms to be inserted = n = 5 Therefore, d = (26 8)/(5 + 1) = 18/6 = 3 Now, a = 8, d = 3 & b = 26 Hence five numbers between 8 and 26 are 11, 14, 17, 20 & 23