Ex 3.3
Last updated at July 24, 2026 by Teachoo
Transcript
Ex 3.3, 22 Prove that cot š„ cot 2š„ ā cot 2š„ cot 3š„ ā cot 3š„ cot š„ = 1 Solving L.H.S. cot x cot 2x ā cot 2x cot 3x ā cot 3x cot x = cot x cot 2x ā cot 3x (cot 2x + cot x) = cot x cot 2x ā cot (2x + x) (cot 2x + cot x) = cot x cot 2x ā ((cot 2x cot x ā 1)/(cot x + cot 2x)) (cot 2x + cot x) = cot x cot 2x ā (cot 2x cot x ā 1) = cot x cot 2x ā cot 2x cot x + 1 = 1 = R.H.S. Hence L.H.S = R.H.S Hence proved