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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


Transcript

Ex 3.2,9 Find the value of the trigonometric function sin (–11"Ο€" /3) sin ((βˆ’πŸπŸ 𝝅)/πŸ‘) = –sin ((11 πœ‹)/3) = –sin ("3 " 𝟐/πŸ‘ " Ο€" ) = –sin ("4Ο€ – " 𝟏/πŸ‘ " Ο€" ) = –sin ((βˆ’πŸ)/πŸ‘ " Ο€" ) Rough So, 11/3 = 3 2/3 = 3 + 2/3 or 4 – 1/3 We take 4 – 𝟏/πŸ‘ as it is even = – ("–sin " (1/3 " Ο€" )) = sin (𝟏/πŸ‘ " Ο€" ) = sin 60Β° = βˆšπŸ‘/𝟐

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.