Question 36 (i) [Case Based] - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards

Last updated at July 23, 2026 by Teachoo

The temperature of a person during an intestinal illness is given by 𝑓(𝑥) = −0.1x^2 + 𝑚𝑥 + 98, 0 ≤x≤12, m being a constant, where 𝑓(𝑥) is the temperature in °F at x days

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Based on the above information answer the following questions.

Question 36 ( i )

Is the function differentiable in the interval (0, 12)? Justify your answer.

part 2 - Question 36 (i) [Case Based] - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

part 3 - Question 36 (i) [Case Based] - CBSE Class 12 Sample Paper for 2023 Boards - Solutions of Sample Papers and Past Year Papers - for Class 12 Boards - Class 12

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Transcript

Question 36 [Case Based] The temperature of a person during an intestinal illness is given by 𝑓(𝑥) = −0.1𝑥^2 + 𝑚𝑥 + 98, 0 ≤𝑥≤12, m being a constant, where 𝑓(𝑥) is the temperature in °F at x daysBased on the above information answer the following questions. Question 36 (i) Is the function differentiable in the interval (0, 12)? Justify your answer.In interval (0, 12) The function is 𝑓(𝑥) = −0.1𝑥^2 + 𝑚𝑥 + 98 Since it is a polynomial function And polynomial functions are differentiable everywhere ∴ f(x) is differentiable in (0, 12)

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