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Ex 7.4, 2 - Sides AB & AC of ABC are extended to points P, Q - Side inequality

  1. Chapter 7 Class 9 Triangles
  2. Serial order wise
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Ex7.4, 2 (Method 1) In the given figure sides AB and AC of ΔABC are extended to points P and Q respectively. Also, ∠PBC < ∠QCB. Show that AC > AB. Similarly, Now, ∠PBC < ∠QCB ∠ A + ∠ ACB < ∠ A + ∠ ABC ∠ ACB < ∠ ABC AB < AC Thus, AC > AB Hence proved. Ex7.4, 2 (Method 2) In the given figure sides AB and AC of ΔABC are extended to points P and Q respectively. Also, ∠PBC < ∠QCB. Show that AC > AB. Similarly, Now, ∠PBC < ∠QCB – ∠PBC > – ∠QCB 180° – ∠PBC > 180° – ∠ QCB

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